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Electronegativity

The atomic nu...

Question

The atomic number of Ni and Cu are 28 and 29 respectively. The electronic configuration $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{10}$ represents:

A

C u^{+}

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B

C u^{2 +}

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C

N i^{2 +}

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D

N i

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Solution

The correct option is A $C u^{+}$

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Similar questions

Q. Calculate the

E

E^{\circ}

N i | N i^{2 +} | | C u^{2 +} | C u

from the following half-cell reactions:

N i^{2 +} + 2 e^{-} \to N i; E^{\circ} = - 0.25 v o l t

C u^{2 +} + 2 e^{-} \to C u; E^{\circ} = + 0.34 v o l t

[N i^{2 +}] = 1 M

[C u^{2 +}] = 10^{- 3} M)

Q. Choose the correct answer from the alternative given.
Amongst

T i F_{6}^{2 -}

C o F

C u_{2}

C l_{2}

N i C l

, which are the colourless species? (atomic number of Ti = 22, Co = 27, Cu = 29, Ni = 28)

T i F_{6}^{2 -}, C o F_{6}^{3 -}, C u_{2} C l_{2}

N i C l_{4}^{2 -}

(Atomic number Ti=22,Co=27,Cu=29,Ni=28 The colourless species are

Q. The pair(s) of complexes wherein both exhibit tetrahedral geometry is(are)
(Note: py = pyridine
Given: Atomic numbers of Fe, Co, Ni and Cu are 26, 27, 28 and 29, respectively)

T i F_{6}^{2 -}, C o F_{6}^{3 -}, {C u}_{2} {C l}_{2}

N i {C l}_{4}^{2 -}

T i = 22, C o = 27, C u = 29, N i = 28

). The colourless species are:

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