The atomic number Z of an element whose k a wavelength is - is 11- The atomic number of an element whose ka- wavelength is 4- is equal to

$K_{α}$ wavelength emitted by an atom of atomic number Z = 11 is $λ$ . The atomic number for an atom that emits $K_{α}$ radiation with wavelength $4 λ$ is

Q. The wavelength of the

k_{a}

line for an element of atomic number

43

λ

. Then the wavelength of the

K_{a}

line for an element of atomic number

29

is?

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The atomic number (Z) of an element whose ka wavelength is λ is 11. The atomic number of an element whose ka, wavelength is 4λ is equal to

The correct option is D 6(Z−1)2λ= constant∴(102)λ=4λ(Z−1)2Z=6

The atomic number $(Z)$ of an element whose $k_{a}$ wavelength is $λ$ is $11$ . The atomic number of an element whose $k_{a}$ , wavelength is $4 λ$ is equal to

The correct option is D $6$
${(Z - 1)}^{2} λ =$ constant
$∴ {(10}^{2}) λ = 4 λ {(Z - 1)}^{2}$
$Z = 6$