The atomic numbers of $A l$ and $C l$ are $13$ and $17$ respectively. What will be the number of electrons in $A l^{3 +}$ and $C l^{-}$ ?

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Solution

The atomic number of aluminium is 13. In the outermost orbit of aluminium atom, 3 electrons are present. Hence, after donating 3 electrons its forms $A l^{+ 3}$ ions, now the number of electrons is 10 and the number of protons is 13. hence, it carries a positive charge.
The atomic number of chlorine is 17. The outermost orbit of chlorine atoms 7 electrons is present. It accepts one electron and forms $C l^{-}$ ions, the number of electrons now is 18 and the number of protons is still 17. Hence, it carries a negative charge.

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The atomic numbers of Al and Cl are 13 and 17 respectively. What will be the number of electrons in Al3+ and Cl−?

The atomic numbers of $A l$ and $C l$ are $13$ and $17$ respectively. What will be the number of electrons in $A l^{3 +}$ and $C l^{-}$ ?