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Mole Concept

The atomic we...

Question

The atomic weight of two elements A and B are 40 and 80 respectively. If $x g$ of A contains y atoms,how many atoms are present in $2 x g$ of B?

$\frac{y}{2}$

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$\frac{y}{4}$

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$y$

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$2 y$

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Solution

The correct option is C
$y$

Number of moles of A = $\frac{x}{40}$

Number of atoms of A = $\frac{x}{40} \times A v o g a d r o n o . = y$ (say)

Or $x$ = $\frac{40 y}{A v o g a r d o n o .}$

Number of moles of B= $\frac{2 x}{80}$

Number of atoms of B= $\frac{2 x}{80} \times A v o g a d r o n o .$

= $\frac{2 x}{80}$ $\times$ $\frac{40 y}{A v o g a r d o n o} \times A v o g a d r o n o . = y$

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The atomic weight of two elements A and B are 40 and 80 respectively. If x g of A contains y atoms,how many atoms are present in 2x g of B?

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