The atomic weights of two elements $A$ and $B$ are $60 u$ and $45 u$ respectively. If $x g m$ of $A$ contains $y$ atoms, how many atoms are there in $3 x g m s$ of $B$ ?

y

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4 y

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8 y

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16 y

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Solution

The correct option is B $y$
No of moles of A= $\frac{x}{60}$

No of atoms of A= $\frac{x}{60}$ XNA= y

NO of moles of B= $\frac{3 x}{45}$ = $\frac{x}{60}$

No of atoms of B= $\frac{x}{60}$ NA

Hence, y is the answer.

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