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Question
The atomic weights of two elements X and Y are 14 and 16 respectively. They form a series of compounds A, B and C, in which the same amount of the elements X and Y are present in the ratio of 1:2:3. If the compound A has 28 parts by weight of X and 16 parts by weight of Y, then the compound B will have 28 parts by weight of X and:
The atomic weights of two elements X and Y are 14 and 16 respectively. They form a series of compounds A, B and C, in which the same amount of the elements X and Y are present in the ratio of 1:2:3. If the compound A has 28 parts by weight of X and 16 parts by weight of Y, then the compound B will have 28 parts by weight of X and:
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Solution
The correct option is A 32 parts by weight of Y
The law of multiple proportions states that if two elements form more than one compound between them, then the ratios of the masses of the second element which combines with fixed masses of the first element will always be a ratio of small whole numbers. If the compound A has 28 parts by weight of X and 16 parts by weight of Y, then fixing X, compound B would have 2 times as much Y as compound A=16×2=32 parts.
The law of multiple proportions states that if two elements form more than one compound between them, then the ratios of the masses of the second element which combines with fixed masses of the first element will always be a ratio of small whole numbers. If the compound A has 28 parts by weight of X and 16 parts by weight of Y, then fixing X, compound B would have 2 times as much Y as compound A=16×2=32 parts.
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