CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Atomic and Ionic Sizes of Lanthanides

The atoms or ...

Question

The atoms or ions possessing unpaired electrons are paramagnetic in nature whereas those possessing electron pairs are diamagnetic in nature. How do you relate the magnetic behavior with electronic arrangement? Justify.

Open in App

Solution

The unpaired electrons produce a magnetic moment towards a single direction. In case of diamagnetic/paired orbital magnetic moment is balanced by the other electron present in the orbital as the other electron filled will have a spin only quantum number opposite to the first one.

Suggest Corrections

thumbs-up

0

Similar questions

Q. Assertion :The atoms or ions possessing unpaired electrons are paramagnetic in nature whereas those possessing electron pairs are diamagnetic in nature. Reason: In diamagnetic substances, the spins of the two electrons cancel out and thus the diamagnetic substances doesnot show any magnetic behaviour . However in paramagnetic substances, the spin of the electron counts and the resultant magnetic moment is not zero.

Q. Assertion :Super oxide ion is paramagnetic whereas peroxide ion is diamagnetic. Reason: Super oxide ion has one unpaired electron whereas per oxide ion has no unpaired electron.

Q. Assertion :Statement

-

1 : Super oxide ion is paramagnetic whereas peroxide ion is diamagnetic. Reason: Statement

-

2 : Super oxide ion has one unpaired electron whereas per oxide ion has no unpaired electron.

Q. Assertion (A):

N O_{2}

is paramagnetic molecule, whereas

N_{2} O_{4}

is diamagnetic
Reason (R): Molecules with unpaired electrons are Diamagnetic.

The substances which contain species with unpaired electrons in their orbitals behave as paramagnetic substances. Such substances are weakly attracted by the magnetic field. The paramagnetism is expressed in terms of magnetic moment. The magnetic moment is related to the number of unpaired electrons according to the following relation:
Magnetic moment,

μ = \sqrt{n (n + 2)} B M

n =

number of unpaired electrons.

B M

stands for Bohr magneton, a unit of magnetic moment.

1 B M = \frac{e h}{4 π m c} = 9.27 \times 10^{- 24} {A m}^{2}

J T^{- 1}

Which of the following ions are diamagnetic?

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Lanthanoids

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Atomic and Ionic Sizes of Lanthanides

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon