The attendance of a class of $45$ boys for $10$ days is given as $40, 30, 35, 45, 44, 41, 38, 44$ and $41$ , then the mean attendance of a class is:

39

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40

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41

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43

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Solution

The correct option is B $40$
In this question one day attendance not given
Given attendance as per Answer are 40,42,30,35,45,44,41,38,44 and41
Then mean = $\frac{40 + 42 + 30 + 35 + 45 + 44 + 41 + 38 + 44 + 41}{10} = \frac{400}{10} = 40$

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The attendance of a class of 45 boys for 10 days is given as 40,30,35,45,44,41,38,44 and 41, then the mean attendance of a class is:

The correct option is B 40In this question one day attendance not givenGiven attendance as per Answer are 40,42,30,35,45,44,41,38,44 and41Then mean =40+42+30+35+45+44+41+38+44+4110=40010=40

The attendance of a class of $45$ boys for $10$ days is given as $40, 30, 35, 45, 44, 41, 38, 44$ and $41$ , then the mean attendance of a class is:

The correct option is B $40$
In this question one day attendance not given
Given attendance as per Answer are 40,42,30,35,45,44,41,38,44 and41
Then mean = $\frac{40 + 42 + 30 + 35 + 45 + 44 + 41 + 38 + 44 + 41}{10} = \frac{400}{10} = 40$