wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The auxiliary circle of family of ellipses, passes through origin and makes intercept of 8 and 6 units on the xāˆ’ axis and the yāˆ’ axis respectively. If eccentricity of all such family of ellipse is 12, then the locus of focus of ellipse will be

A
4x2+4y2+32x24y+75=0
No worries! Weā€˜ve got your back. Try BYJUā€˜S free classes today!
B
4x2+4y232x24y+75=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
4x2+4y232x+24y+75=0
No worries! Weā€˜ve got your back. Try BYJUā€˜S free classes today!
D
4x2+4y232x24y75=0
No worries! Weā€˜ve got your back. Try BYJUā€˜S free classes today!
Open in App
Solution

The correct option is B 4x2+4y232x24y+75=0


Centre of family of ellipse is (0+82,6+02)=(4,3)

Length of major axis 2a=82+62
a=5

Distance of focus from centre =ae
=5×12=52

If (h,k) is the coordinates of focus, then
(h4)2+(k3)2=254
Hence, required locus is
4x2+4y232x24y+75=0

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon