Question

The average $7$ consecutive numbers is $20$. The largest of these number is:

• A. $20$
• B. $22$
• C. $23$
• D. $24$

Answer 1

Answer: (C)

$23$

Let'a' be any number

Given

$20=\frac{a+(a+1)+(a+2)+(a+3)+(a+4)+(a+5)+(a+6)}{7}$

$\Rightarrow 140=7a+21$

$\Rightarrow 7a=119$

$\Rightarrow a=\frac{119}{7}$

$a=17$

Hence, Highest number $=a+6$

$=17+6$

$=23$