The average age of 40 students of a class is 15 years. When 10 new students are admitted, the average is increased by 0.2 year. The average age of the new students is

15.2 years

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16 years

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16.2 years

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16.4 years

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Solution

The correct option is B 16 years
Total age of 40 old students $= 40 \times 15 = 600 y e a r s$ .
Total age of 40 old and 10 new students $= 50 \times 15.2 = 760 y e a r s$
$∴$ Total age of 10 new students $= 760 - 600 = 160 y e a r s$
$∴$ Required average age $= \frac{160}{10} = 16 y e a r s$

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The average age of 40 students of a class is 15 years. When 10 new students are admitted, the average is increased by 0.2 year. The average age of the new students is

The correct option is B 16 yearsTotal age of 40 old students =40×15=600years.Total age of 40 old and 10 new students =50×15.2=760years∴ Total age of 10 new students =760−600=160years∴ Required average age =16010=16years

The correct option is B 16 years
Total age of 40 old students $= 40 \times 15 = 600 y e a r s$ .
Total age of 40 old and 10 new students $= 50 \times 15.2 = 760 y e a r s$
$∴$ Total age of 10 new students $= 760 - 600 = 160 y e a r s$
$∴$ Required average age $= \frac{160}{10} = 16 y e a r s$