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Question

The average age of Harsh, Wyatt and Charan together 3 years ago was 27 years and that of Wyatt and Charan 5 years ago was 20 years. What is the present age of the Harsh?


A

30

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B

40

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C

45

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D

35

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E

50

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Solution

The correct option is B

40


Let the present age of the Harsh = h

Present age of the Wyatt = w

Present age of the Charan = c

3 years ago, average age of Harsh, Wyatt and Charan = 27

Sum of age of Harsh, Wyatt and Charan before 3 years =3×27=81

(h-3) + (w-3) + (c-3) = 81

h + w + c = 81+9 = 90 -------------------equation(1)

5 years ago, average age of Wyatt and Charan = 20

Sum of age of Wyatt and Charan before 5 years =2×20=40

(w-5) + (c-5) = 40 => w + c = 40+10 = 50 -------------------equation(2) Substituting equation(2) in equation(1)

h + 50 = 90 => h = 90 - 50 = 40

Present age of Harsh = 40 years


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