The average ages of $4$ member, each having the age difference of $2$ yrs is $54$ yrs.What is the sum of the ages of the youngest and oldest family member ?

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Solution

Total age of Four members $= 54 \times 4 = 216$
Let the age of first peron be $x$
Age of second person = $x + 2$
Age of third person = $x + 4$
Age of Fourth person = $x + 6$
So $4 x + 12 = 216 \to x = 51$
Age of youngest member = $51$ Years
Age of oldest member = $57$ years
Sum of ages of both = $51 + 57 = 108$ years

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The average ages of 4 member, each having the age difference of 2yrs is 54 yrs.What is the sum of the ages of the youngest and oldest family member ?

Total age of Four members =54×4=216Let the age of first peron be x Age of second person = x+2Age of third person = x+4Age of Fourth person = x+6So 4x+12=216→x=51Age of youngest member = 51 YearsAge of oldest member = 57 yearsSum of ages of both = 51+57=108 years

The average ages of $4$ member, each having the age difference of $2$ yrs is $54$ yrs.What is the sum of the ages of the youngest and oldest family member ?