The average amount of rainfall for 52 weeks of a particular year were in Arithmetic Progression. If the average rainfall in the 26^th week was 54 cm and that in the next week was 56 cm, then what is the total rainfall in that entire year? [ignore the days of the year that are beyond the 52 weeks]

2520 cm

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2860 cm

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2740 cm

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2760 cm

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Solution

The correct option is B 2860 cm
As the average amounts of rainfall are in AP, the exact middle value of these averages will be the average rainfall of the entire year.

$M i d d l e v a l u e o f t h e a v e r a g e s = \frac{54 + 56}{2} = 55$

There are 52 weeks.

So, the total rainfall = 55 × 52 = 2860 cm

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The average amount of rainfall for 52 weeks of a particular year were in Arithmetic Progression. If the average rainfall in the 26th week was 54 cm and that in the next week was 56 cm, then what is the total rainfall in that entire year? [ignore the days of the year that are beyond the 52 weeks]

The correct option is B 2860 cmAs the average amounts of rainfall are in AP, the exact middle value of these averages will be the average rainfall of the entire year. Middle value of the averages =54+562=55 There are 52 weeks. So, the total rainfall = 55 × 52 = 2860 cm

The average amount of rainfall for 52 weeks of a particular year were in Arithmetic Progression. If the average rainfall in the 26^th week was 54 cm and that in the next week was 56 cm, then what is the total rainfall in that entire year? [ignore the days of the year that are beyond the 52 weeks]