The average atomic mass of ${C l}^{35}$ & ${C l}^{37}$ is 35.5. Then % abudance ${C l}^{35}$ of is

25%

No worries! We‘ve got your back. Try BYJU‘S free classes today!

75%

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

80%

No worries! We‘ve got your back. Try BYJU‘S free classes today!

20%

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
75%

AM = $\frac{x 35 + (100 - x) 37}{100}$

3550 = 3700 - 2x

2x = 150

x = 75%

Suggest Corrections

Similar questions

Q. What will be the ratio of

C l^{35}

and

C l^{37}

respectively in chlorine if the average atomic mass of chlorine is 35.5?

Q. What will be the ratio of

C l^{35}

and

C l^{37}

respectively in ordinary chlorine if the atomic weight of chlorine is 35.5 ?

{C l}^{35}

and

{C l}^{37}

are:

Naturally occurring chlorine consists of two isotopes whose atomic weights are 35 and 37. The atomic weight of natural chlorine is 35.5, then what is the ratio of $C l^{35} t o C l^{37}$ ?

Q. Difference in

_{17} {C l}^{35}

and

_{17} {C l}^{37}

is of:

Join BYJU'S Learning Program

The average atomic mass of Cl35 & Cl37 is 35.5. Then % abudance Cl35 of is

The correct option is B 75% AM = x35+(100−x)37100 3550 = 3700 - 2x 2x = 150 x = 75%

The average atomic mass of ${C l}^{35}$ & ${C l}^{37}$ is 35.5. Then % abudance ${C l}^{35}$ of is

The correct option is B
75%

AM = $\frac{x 35 + (100 - x) 37}{100}$

3550 = 3700 - 2x

2x = 150

x = 75%