Question

The average binding energy per nucleon is maximum for the nucleus

• A. ${}_2{H}^4$
• B. ${}_8{O}^{16}$
• C. ${}_{26}F{e}^{56}$
• D. ${}_{92}{U}^{238}$

Answer 1

The correct option is C ${}_{26}F{e}^{56}$

Binding energy per nucleon increases with atomic number. The greater the binding energy per nucleon the more stable is the nucleus.
For ${}_{26}F{e}^{56}$ number of nucleons is $56.$
This is most stable nucleus, since maximum energy is needed to pull a nucleon away from it.