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Degree of Freedom

The average d...

Question

The average degree of freedom of a gas is 6. Gas performs 50 J work when it expands at constant pressure. The heat absorbed by the gas is

A

100 J

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B

200 J

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C

50 J

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D

25 J

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Solution

The correct option is B
200 J

dW=PdV=nRdT=50

$Q = n C_{p} d T$

$= n (1 + \frac{f}{2}) R d T$

$= (1 + \frac{6}{2}) n R d T$

$= 4 \times 50 = 200 J$

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