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Standard XII

Physics

Bulk Modulus

The average d...

Question

The average depth of Indian Ocean is about $3000 m$ . The fractional compression, $\frac{Δ V}{V}$ of water at the bottom of the ocean (given that the bulk modulus of the water = $2.2 \times 10^{9} {Nm}^{- 2} {and g=10 ms}^{- 2}$ , assuming density of water remains constant) is

0.82 %

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0.91 %

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1.36 %

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1.52 %

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Solution

The correct option is C $1.36 %$
$| B | = | \frac{- Δ P}{Δ V / V} |$
$\frac{Δ V}{V} = \frac{Δ P}{B}$
But
$\begin{matrix} Δ P & = ρ g h = 1000 \times 10 \times 3000 = 3 \times 10^{7} \end{matrix}$
So, $\frac{Δ V}{V} = \frac{Δ P}{B} = \frac{3 \times 10^{7}}{2 \cdot 2 \times 10^{9}} = 1.36$ %

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Similar questions

Q. The average depth of Indian Ocean is about

3000 m

. The fractional compression,

\frac{Δ V}{V}

of water at the bottom of the ocean (given that the bulk modulus of the water =

2.2 \times 10^{9} {Nm}^{- 2} {and g=10 ms}^{- 2}

, assuming density of water remains constant) is

The average depth of Indian Ocean is about 3000 m. Calculate the fractional compression, $\frac{Δ V}{V}$ of water at the bottom of the ocean, given that the bulk modulus of water is $2.2 \times 10^{9} N m^{- 2}$ (consider $g = 10 m s^{- 2}$ )

Q. The average depth of Indian Ocean is about

3000 m

. The fractional compression,

\frac{Δ V}{V}

of water at the bottom of the ocean is then
(Given: Bulk modulus of the water

= 2.2 \times 10^{9} N m^{- 2}

and

g = 10 m s^{- 2}

)

Q. The average depth of Indian ocean is about 3000 m Bulk Modulus of water is

2.2 \times 10^{4} N / m^{2}

g = 10 m / s^{2}

,then the fractional compression is

\frac{Δ V}{V}

of water at the bottom of Indian Ocean is:

Q. The average depth of Indian ocean is about

3000 m

. The value of fractional compression

\frac{Δ V}{V}

of water at the bottom of the ocean is:

[Given that the bulk modulus of water is

2.2 \times 10^{9} N m^{- 2}

g = 9.8 m s^{- 2}

and

ρ_{H_{2} O} = 1000 k g . m^{- 3}

]

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The average depth of Indian Ocean is about 3000 m. The fractional compression, ΔVVof water at the bottom of the ocean (given that the bulk modulus of the water =2.2×109Nm−2 and g=10 ms−2, assuming density of water remains constant) is

The correct option is C 1.36%|B|=|−ΔPΔV/V| ΔVV=ΔPB But ΔP=ρgh=1000×10×3000=3×107 So, ΔVV=ΔPB=3×1072⋅2×109=1.36%

The average depth of Indian Ocean is about $3000 m$ . The fractional compression, $\frac{Δ V}{V}$ of water at the bottom of the ocean (given that the bulk modulus of the water = $2.2 \times 10^{9} {Nm}^{- 2} {and g=10 ms}^{- 2}$ , assuming density of water remains constant) is

The correct option is C $1.36 %$
$| B | = | \frac{- Δ P}{Δ V / V} |$
$\frac{Δ V}{V} = \frac{Δ P}{B}$
But
$\begin{matrix} Δ P & = ρ g h = 1000 \times 10 \times 3000 = 3 \times 10^{7} \end{matrix}$
So, $\frac{Δ V}{V} = \frac{Δ P}{B} = \frac{3 \times 10^{7}}{2 \cdot 2 \times 10^{9}} = 1.36$ %