The average energy intensity contribution of electric field in an EM wave is $I .$ The net average energy intensity of EM wave is

I

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\frac{I}{2}

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2 I

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4 I

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Solution

The correct option is C $2 I$
In electromagnetic waves, contribution of magnetic and electric field in average energy intensity is same.

So, $I_{B} = I_{E} = I$

$\Rightarrow I_{n e t} = I_{E} + I_{B} = 2 I$

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