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Forced Oscillations

The average f...

Question

The average force necessary to stop a hammer with 25 N-s momentum in 0.05s expressed in N is :

500

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125

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250

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Solution

The correct option is A 500
Impulse $=$ Force $\times$ time
$25 = F \times 0.05$
$F = \frac{25}{0.05} = 500 N$

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