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Impulsive Forces in Collision

The average f...

Question

The average force necessary to stop a hammer with 25 Ns momentum in 0.05 s expressed in N is

A

25

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B

50

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C

125

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D

500

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Solution

The correct option is D 500
Force $= \frac{I m p u l s e}{T i m e}$
$= \frac{25}{0.05} = 500 N$

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