Question

The average kinetic energy of a molecule of a perfect gas is :

• A. $\frac{2}{3}kT$
• B. $1.5kT$
• C. $2.5kT$
• D. none of these

Answer 1

The correct option is B $1.5kT$

Average kinetic energy of a molecule is given by:
$K.E=\frac{3}{2}kT=1.5kT$
Where k is the Boltzmann constant.
Hence option B is correct,