The average kinetic energy of oxygen gas per molecule at $27^{o} C$ is ____ Cals/ mole.
[R $=$ 2 cal]

450

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1800

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900

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1350

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Solution

The correct option is C 900
$K E = \frac{3}{2} n R T$

$K E = \frac{3 \times 2 \times 300}{2}$

K.E. of oxygen gas per molecule is 900 cals.

Hence, the correct option is $C$

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