The average kinetic energy of thermal neutron is of the order of :
(Boltzmann's constant $k_{B} = 8 \times 10^{- 5} e V / K$ )

0.03 e V

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3 e V

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3 k e V

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3 M e V

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Solution

The correct option is A $0.03 e V$
Thermal neutron, any free neutron (one that is not bound within an atomic nucleus) that has an average energy of motion (kinetic energy) corresponding to the average energy of the particles of the ambient materials.
Average Kinetic Energy=kT=0.03eV

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The average kinetic energy of thermal neutron is of the order of :(Boltzmann's constant kB=8×10−5eV/K)

The correct option is A 0.03eVThermal neutron, any free neutron (one that is not bound within an atomic nucleus) that has an average energy of motion (kinetic energy) corresponding to the average energy of the particles of the ambient materials. Average Kinetic Energy=kT=0.03eV

The average kinetic energy of thermal neutron is of the order of :
(Boltzmann's constant $k_{B} = 8 \times 10^{- 5} e V / K$ )

The correct option is A $0.03 e V$
Thermal neutron, any free neutron (one that is not bound within an atomic nucleus) that has an average energy of motion (kinetic energy) corresponding to the average energy of the particles of the ambient materials.
Average Kinetic Energy=kT=0.03eV