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Question

The average length of time required to complete a jury questionnaire is 40 minutes, with a standard deviation of 5 minutes. What is the probability that it will take a prospective juror between 30 and 50 minutes to complete the questionnaire?

A
About 85%
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B
About 90%
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C
About 95%
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D
none
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Solution

The correct option is C About 95%
For normal distribution ,  P(x)=1/(sigmasqrt(2pi))e^(-(x-mu)^2/(2sigma^2))
Average length of time required to complete a jury questionnaire is 4040 minutes
Mean (μ)=40
standard deviation(σ)=5
Probability that it will take 30 to 50 min i.e, P(30<x<50)
For standard normal distribution curve
Z=(x-μ)/σ
(30-40)/5<(x-μ)/σ<(50-40)/5
-2<Z<2
Image result for normal distribution curve
For standard normal distribution mean shifted to zero,  P(x)dx=1/(sqrt(2pi))e^(-z^2/2)dz.
Also,P(-2<Z<2)=area of the region between -1 to 1 that is approximately equal to=95%





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