The average marks in English of a class of 24 students is 56. If the marks of three students were misread as 44, 45 and 61 in lieu of the actual marks 48, 59 and 67 respectively, then what would be the correct average?

56.6

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57.5

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Solution

The correct option is B 57
Total marks $= 24 \times 56 = 1344$
Total of actual marks $= 1344 - (44 + 45 + 61) + (48 + 59 + 67) = 1368$
Actual average $= \frac{1368}{24} = 57$

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The average marks in English of a class of 24 students is 56. If the marks of three students were misread as 44, 45 and 61 in lieu of the actual marks 48, 59 and 67 respectively, then what would be the correct average?

The correct option is B 57Total marks =24×56=1344Total of actual marks =1344−(44+45+61)+(48+59+67)=1368Actual average =136824=57

The correct option is B 57
Total marks $= 24 \times 56 = 1344$
Total of actual marks $= 1344 - (44 + 45 + 61) + (48 + 59 + 67) = 1368$
Actual average $= \frac{1368}{24} = 57$