Question

The average marks obtained by five students A, B, C, D, and E is $52\frac{3}{5}$ and the average marks obtained by A,C, and D are $53\frac{2}{3}$, and the average marks Obtained by B , C and E are $52\frac{3}{3}$, then the marks obtained by C were

• A. 56
• B. 53
• C. 57
• D. 60

Answer 1

Answer: (A)

56

Total marks obtained by A + B + C + D + E = 5 x 52 = $5\times \frac{263}{5}=263$ .....(1)
Total marks obtained by A + C + D = $3\times 53\frac{2}{3}=3\times \frac{161}{3}=161$ .....(2)
Total marks obtained by B + C + E = 3 x 52$\frac{2}{3}=3\times \frac{158}{3}=158$ .....(3)
$\therefore$ (1) - (2)
$\Rightarrow$ Marks obtained by B + E = 263 - 161 = 102 .....(4)
(3) - (4)
$\Rightarrow$ Marks obtained by C = 158 - 102 = 56