The average marks of boys in a class is 52 and that of girls is 42. The average marks of boys and girls together is 50. The percentage of boys in the class is

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Solution

The correct option is C 80
Let the number of boys and girl are x and y.
$∴ 52 x + 42 y = 50 (x + y) \Rightarrow 2 x = 8 y \Rightarrow x = 4 y$
Total number of students in the class
$= x + y = 4 y + y = 5 y ∴$ Required percentage of boys $= \frac{4 y}{5 y} \times 100 = 80$

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The average marks of boys in a class is 52 and that of girls is 42. The average marks of boys and girls together is 50. The percentage of boys in the class is

The correct option is C 80Let the number of boys and girl are x and y. ∴52x+42y=50(x+y)⇒2x=8y⇒x=4y Total number of students in the class =x+y=4y+y=5y∴ Required percentage of boys =4y5y×100=80

The correct option is C 80
Let the number of boys and girl are x and y.
$∴ 52 x + 42 y = 50 (x + y) \Rightarrow 2 x = 8 y \Rightarrow x = 4 y$
Total number of students in the class
$= x + y = 4 y + y = 5 y ∴$ Required percentage of boys $= \frac{4 y}{5 y} \times 100 = 80$