Question

The average of $11$ numbers is $10$. When one number is eliminated, the average of the remaining numbers is $9.3$. What is the eliminated number?

• A. $15$
• B. $20$
• C. $13$
• D. $17$

Answer 1

The correct option is D $17$

If the average of $11$ numbers is $10$, their sum is $11\times 10=110$. After one number is eliminated,the average is $9.3$, so the sum of the $10$ remaining numbers is $10\times 9.3=93$. The number eliminated is the difference between these sums: $110-93=17$.