In the given frequency distribution, which is the median term?
$\begin{matrix} Age in years & Number of people 15 & 3 16 & 8 17 & 10 18 & 10 19 & 5 20 & 4 \end{matrix}$

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The average of 15 numbers is 18. The average of 1st 8 is 19 and the last 8 is 17 then the 8th number is?

The correct option is C 18If average of 15 no. =18 then sum if 15 no. =15×18=270If average of 1st 8 = 19 sum =8×17=152average of last 8 = 17 sum =17×8=136TO FIND 8TH NO (136+152)−270=288−270=18

The average of $15$ numbers is $18$ . The average of $1$ st $8$ is $19$ and the last $8$ is $17$ then the $8$ th number is?

The correct option is C $18$
If average of 15 no. $= 18$ then sum if 15 no. $= 15 \times 18 = 270$
If average of 1st 8 = 19
sum $= 8 \times 17 = 152$
average of last 8 = 17 sum $= 17 \times 8 = 136$
TO FIND 8TH NO
$(136 + 152) - 270 = 288 - 270 = 18$