The average of 4 distinct prime numbers a, b, c, d is 35, where a < b < c < d. a and d are equidistant from 36 and b and c are equidistant from 34 and a, b are equidistant from 30 and c and d are equidistant from 40. The difference between a and d is :

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Solution

The correct option is B 14
Given that a < b < c < d

The only possible prime number between 30 and 34 is 31
Hence b = 31, therefore a = 29
Similarly c = 37 and d = 43
Therefore d - a = 43 - 29 = 14

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