The average of 5 terms is 50. If the first 4 terms are 45, 42, 119, and 84, what will be the last term?

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Solution

Sum of all the terms $= 250$
Sum of first four terms $= 45 + 42 + 119 + 84 = 290$
So, the 5th term should be $250 - 290 = - 40.$

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The average of 5 terms is 50. If the first 4 terms are 45, 42, 119, and 84, what will be the last term?

Sum of all the terms =250Sum of first four terms =45+42+119+84=290So, the 5th term should be 250−290=−40.

Sum of all the terms $= 250$
Sum of first four terms $= 45 + 42 + 119 + 84 = 290$
So, the 5th term should be $250 - 290 = - 40.$