Question

The average of $6$ numbers is $30$. If one number is excluded, the average of the remaining numbers is $29$. The excluded number is

• A. $29$
• B. $30$
• C. $35$
• D. $45$

Answer 1

Answer: (C)

$35$

According to the problem,

therefore,

sum of $6$ numbers $=30\times 6=180$

sum of five numbers $=29\times 5=145$

Hence, the number that was excluded $=180-145=35$.