The average of a, b, c, and d is 6. If the average of c and d is 3. What is the average of a and b?

Open in App

Solution

$\frac{a + b + c + d}{4} = 6$ ...(1)
Also, $\frac{c + d}{2} = 3$
$c + d = 6$
$\frac{a + b + 6}{4} = 6$
$a + b = 18$
So, average = $\frac{a + b}{2} = 9$ .

Suggest Corrections

Similar questions

Q. If the average of a, b,c,d is the average of b and c, then the value of a – b – c + d is ___________.

The average weight of A, B and C is $54 \frac{1}{3}$ kg, while the average weight of B, D and E is $53$ kg.
What is the average weight of A, B, C, D and E?

Q. The average age of 3 boys, A, B and C is 54 \frac{1}{3} Kg. while the average of 3 boys B, D and E is 52 Kg. What will be the average weight of A, B, C, D and E?

Q. If the average of a, b, c, d, and e is 38, average of a, c, and e is 28, and average of b and d is

n^{2} + 4

, then the value of n is

\pm k

. Find the value of k.

Q. If the average of

a, b, c

and

d

is the average of

b

and

c

, then which one of the following is necessarily true?

Join BYJU'S Learning Program

The average of a, b, c, and d is 6. If the average of c and d is 3. What is the average of a and b?

a+b+c+d4=6 ...(1) Also, c+d2=3 c+d=6 a+b+64=6 a+b=18 So, average = a+b2=9.

$\frac{a + b + c + d}{4} = 6$ ...(1)
Also, $\frac{c + d}{2} = 3$
$c + d = 6$
$\frac{a + b + 6}{4} = 6$
$a + b = 18$
So, average = $\frac{a + b}{2} = 9$ .