Question

The average of $1\frac{1}{6},2\frac{1}{3},6\frac{2}{3}$ and $8\frac{5}{6}$ is:

• A. $6\frac{3}{4}$
• B. $5\frac{3}{4}$
• C. $4\frac{3}{4}$
• D. $3\frac{3}{4}$

Answer 1

The correct option is C $4\frac{3}{4}$

Given, the elements are $1\frac{1}{6},2\frac{1}{3},6\frac{2}{3},8\frac{5}{6}$.

The number of elements $=4$.

Sum of the elements $=1\frac{1}{6}+2\frac{1}{3}+6\frac{2}{3}+8\frac{5}{6}$

$=\frac{7}{6}+\frac{7}{3}+\frac{20}{3}+\frac{53}{6}$

$=\frac{7+14+40+53}{6}=\frac{114}{6}=19$.

We know, Mean is given by,

$\text{Mean}=\frac{\text{Sum of the elements}}{\text{Total number of elements}}$.

$\therefore$ Average/Mean $=\frac{19}{4}=4\frac{3}{4}$.

Hence, option $C$ is correct.