The average of eight numbers is x and the average of two of these is y. If the average of the remaining numbers is z, then

x = y + 3z

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x = 2y + 3z

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4x = 2y + z

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4x = y + 3z

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2x = 2y + 3z

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Solution

The correct option is D
4x = y + 3z

Average of 8 numbers = x

$\Rightarrow$ Sum of 8 numbers = 8x

Average of the 2 numbers = y

$\Rightarrow$ Sum of these 2 numbers = 2y

Average of the remaining 6 numbers = z

$\Rightarrow$ Sum of the remaining 6 numbers = 6z

Now we know that 8x = 2y + 6z

$\Rightarrow$ 4x = y + 3z

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The average of eight numbers is x and the average of two of these is y. If the average of the remaining numbers is z, then

The correct option is D 4x = y + 3z Average of 8 numbers = x ⇒ Sum of 8 numbers = 8x Average of the 2 numbers = y ⇒ Sum of these 2 numbers = 2y Average of the remaining 6 numbers = z ⇒ Sum of the remaining 6 numbers = 6z Now we know that 8x = 2y + 6z ⇒ 4x = y + 3z