The average of marks of $12$ students is $15$ . The marks of a student who scored zero were wrongly taken as $18$ and average was determined. The correct average marks is _________.

15

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14.5

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13.5

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12

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Solution

The correct option is D $13.5$
Given, average of marks of $12$ students is $15$ .
Therefore, $sum = 12 \times 15 = 180$
The marks of a student were wrongly taken as $18$ , while he scored $0$ .
Thus corrected sum $= 180 - 18 + 0 = 162$
$= \frac{162}{12} = 13.5$

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The average of marks of 12 students is 15. The marks of a student who scored zero were wrongly taken as 18 and average was determined. The correct average marks is _________.

The correct option is D 13.5Given, average of marks of 12 students is 15.Therefore, sum=12×15=180The marks of a student were wrongly taken as 18, while he scored 0.Thus corrected sum =180−18+0=162=16212=13.5

The average of marks of $12$ students is $15$ . The marks of a student who scored zero were wrongly taken as $18$ and average was determined. The correct average marks is _________.

The correct option is D $13.5$
Given, average of marks of $12$ students is $15$ .
Therefore, $sum = 12 \times 15 = 180$
The marks of a student were wrongly taken as $18$ , while he scored $0$ .
Thus corrected sum $= 180 - 18 + 0 = 162$
$= \frac{162}{12} = 13.5$