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Question

The average of n numbers x1,x2,x3,..........,xn is M. If xn is replaced by x’, then new average is

A
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Solution

The correct option is B
M=x1+x2+x3.........xnn
nM=x1+x2+x3+........xn1
nMxn+x!n=x1+x2+x3+.......xn1+x!n
New average=nMxn+x!n

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