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Question

The average of n numbers x1,x2,...,xn is M. If xn is replaced by x, then the new average is

A
Mxn+xn
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B
(n1)M+xn
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C
nMxn+xn
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D
Mxn+x
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Solution

The correct option is A nMxn+xn
We have,
M=x1+x2+...+xnn
x1+x2+...+xn1+xn=nM
x1+x2+...+xn1=nMxn
Let M be the average of x1,x2,...,xn1,x. Then
M=x1+x2+...+xn1+xn M=nMxn+xn

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