Question

The average of the two middle rational numbers, if $\frac{4}{7}$, $\frac{1}{3}$, $\frac{2}{3}$, $\frac{5}{9}$ are arranged in ascending order is:

• A. $\frac{4}{9}$
• B. $\frac{71}{63}$
• C. $\frac{2}{9}$
• D. $\frac{71}{126}$

Answer 1

The correct option is D $\frac{71}{126}$

Given a set of fractions $:\frac{4}{7},\frac{1}{3},\frac{2}{3},\frac{5}{9}$

Arranging the given fractions in ascending order, we get

$\frac{1}{3}<\frac{5}{9}<\frac{4}{7}<\frac{2}{3}$

$\therefore$ Two middle rational numbers are $\frac{5}{9}$ and $\frac{4}{7}$

Average $=\frac{\frac{5}{9}+\frac{4}{7}}{2}=\frac{\frac{35+36}{63}}{2}$

$=\frac{71}{126}$