The average of x numbers is y. Out of these numbers one number is 10. What will be the average of the remaining numbers,if 10 is omitted from the group of numbers?
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Solution
The average of x numbers = y So the sum of the x numbers= x * y If 10 is omitted from the group of numbers, the sum =( x* y )- 10 Remaining number of numbers= x - 1 Therefore new average= [(x*y) - 10] / (x-1)