The average power dissipated in a pure inductor is

$\frac{V I^{2}}{4}$

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$\frac{1}{2} V I$

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$z e r o$

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$V I^{2}$

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Solution

The correct option is C
$z e r o$

$P_{a v} = V I c o s ϕ ϕ = \frac{π}{2}, P_{a v} = 0$

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