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Power

The average p...

Question

The average power required to lift a $100 k g$ mass through a height of $50$ metres in approximately $50$ seconds would be

50 J / s

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5000 J / s

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100 J / s

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980 J / s

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Solution

The correct option is D $980 J / s$
$m a s s m = 100 k g, d i s t a n c e S = 50 m, t i m e t = 50 s$

Power $P$ $= \frac{F . S}{t} = \frac{m g . S}{t} = \frac{100 \times 9.8 \times 50}{50} = 980 J / s$

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