Question

The average price of $10$ books is Rs. $12$ while the average price of $8$ of these books is RS. $11.75$. Of the remaining two books, if the price of one book is $60$% more than the price of the toher, what is the price of each of these two books?

• A. Rs. $5$, Rs, $7.50$
• B. Rs. $8$, Rs, $12$
• C. Rs. $10$, Rs, $16$
• D. Rs. $12$, Rs, $14$

Answer 1

Answer: (C)

Rs. $10$, Rs, $16$

Total price of the two books $=12\times 10-11.75\times 8$

$=120-94$

$=Rs.26$

Let the price of one book be Rs.x

Then,

The price of other book $=x+60\%ofx$

$=x+\frac{3}{5}x$

$=\frac{8}{5}x$

So, $x+\frac{8}{5}x=26$

$\frac{13}{5}x=26$

$x=\frac{26\times 5}{13}$

$x=10$

$\frac{8}{5}x=\frac{8}{5}\times 10=16$

The price of the two books are Rs.10 and Rs.16.