The average resisting force that must act on a $5 k g$ mass to reduce its speed from $65$ to $15$ ms $^{- 1}$ in $2 s$ is-

12.5 N

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125 N

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1250 N

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None of these.

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Solution

The correct option is B $125 N$
$F_{a v g} = m a$

$F_{a v g} = m (\frac{v - u}{t})$

Here, $v = 65$ m/s $^{2}$ , $u = 15$ m/s $^{2}$ , $t = 2$ s, and $m = 5$ kg

$\Rightarrow F_{a v g} = 5 (\frac{65 - 15}{2}) = 125$ N

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The average resisting force that must act on a 5kg mass to reduce its speed from 65 to 15 ms−1 in 2s is-

The correct option is B 125NFavg=maFavg=m(v−ut)Here, v=65 m/s2, u=15 m/s2, t=2 s, and m=5 kg⇒Favg=5(65−152)=125N

The average resisting force that must act on a $5 k g$ mass to reduce its speed from $65$ to $15$ ms $^{- 1}$ in $2 s$ is-

The correct option is B $125 N$
$F_{a v g} = m a$

$F_{a v g} = m (\frac{v - u}{t})$

Here, $v = 65$ m/s $^{2}$ , $u = 15$ m/s $^{2}$ , $t = 2$ s, and $m = 5$ kg

$\Rightarrow F_{a v g} = 5 (\frac{65 - 15}{2}) = 125$ N