The average resisting force that must act on a 5 kg mass to reduce its speed from 65 1excm- -1exs- to 0-15 1exm- -1exs- in 0-2s is-

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Simple Harmonic Oscillation

The average r...

Question

The average resisting force that must act on a $5 k g$ mass to reduce its speed from $65 \frac{c m}{s}$ to $0.15 \frac{m}{s}$ in 0.2s is:

12.5 N

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25 N

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50 N

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100 N

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Solution

The correct option is A
12.5 N

Step-1: Given data
Mass of the object, $m = 5 k g$
Initial speed of the object, $u = 65 c m / s = 0.65 m / s$ .
Final speed of the object, $v = 15 c m / s = 0.15 m / s$ .
Time, $t = 0.2 s$ .
Step-2: Finding average resisting force
Using Newton's second law of motion:
$F = m a$
$F = m \times \frac{v - u}{t}$
$F = 5 \times \frac{0.15 - 0.65}{0.2} F = - 12.5 N$
Hence average resisting force is $12.5 N$ and the correct option is (a).

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The average resisting force that must act on a 5kg mass to reduce its speed from 65cms to 0.15ms in 0.2s is:

The average resisting force that must act on a $5 k g$ mass to reduce its speed from $65 \frac{c m}{s}$ to $0.15 \frac{m}{s}$ in 0.2s is: