The average resisting force that must act on a $5 k g$ mass to reduce its speed from $65 {c m s}^{- 1}$ to $15 {c m s}^{- 1}$ in $0.2 s$ is

12.5 N

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25 N

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50 N

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100 N

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Solution

The correct option is D $12.5 N$
Initial speed $u = 0.65 m / s$
Final speed $v = 0.15 m / s$
Time $t = 0.2 s$
Retardation $a = \frac{u - v}{t} = \frac{0.65 - 0.15}{0.2} = 2.5 m / s^{2}$
Average resisting force $F = m a = 5 \times 2.5 = 12.5 N$
Option A is correct.

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