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Standard XII

Chemistry

Enthalpy of Solution

The average S...

Question

The average $S - F$ bond energy in $k J m o l^{- 1}$ of $S F_{6}$ is _____.(Rounded off to the nearest integer

[Given : The values of standard enthalpy of formation of $S F_{6} (g), S (g) a n d F (g)$ are - 1100, 275 and 80 kJ $m o l^{- 1}$ respectively]

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Solution

$S F_{6} (g), S (g) a n d F (g)$

$S F_{6} (g) \to S (g) + 6 F (g)$

$Δ H = Δ H_{f} (p r o d u c t) - Δ H_{f} (r e a c t a n t)$
$Δ H^{0} = Δ H_{f}^{0} (S) + 6 Δ H_{f}^{0} (F) - Δ H_{f}^{0} (S F_{6})$
$= 275 + 6 \times 80 - (- 1100)$
= $1855 k J m o l^{- 1}$
Also, $Δ H^{0} = 6 Δ H_{S - F}$
$∴ Δ H_{S - F} = \frac{1855}{6} = 309.17 = 309 k J m o l^{- 1}$

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Similar questions

Q. The average S–F bond energy in

k J m o l^{- 1}

S F_{6}

is______. (Rounded off to the nearest integer)
[Given : The values of standard enthalpy of formation of

S F_{6} (g), S (g) and F (g) are 1100, 275 and 80 k J m o l^{- 1}

respectively.]

Q. The value of standard enthalpy of formation of

S F_{6} (g), S (g) a n d F (g) a r e - 1100, 275, 80 k J / m o l

respectively. The average bond energy of

S F_{6}

(in kJ/mol) is
(Give your answer upto two decimal points)

The standard heat of formation values of $S F_{6} (g)$ , $S (g)$ and $F (g)$ are: $- 1100, 275$ and $80 K J m o l^{- 1}$ respectively. Then the average S - F bond energy in $S F_{6}$ is:

Q. The value of standard enthalpy of formation of

S F_{6} (g) S (g)

and

F (g)

are

- 1100, 275

and

80 k J m o l^{- 1}

respectively. The average

S - F

bond ethalpy is

S F_{6}

is :

Q. The average

S - F

bond energy in

S F_{6}

if the

Δ H_{f}^{o}

values are

- 1100, + 275

and

+ 80

kJ/mol respectively for

S F_{6}

(g),

S

(g) and

F

(g) is:

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The average S−F bond energy in kJ mol−1 of SF6 is _____.(Rounded off to the nearest integer [Given : The values of standard enthalpy of formation of SF6(g), S(g)andF(g) are - 1100, 275 and 80 kJ mol−1 respectively]

SF6(g),S(g) and F(g) SF6(g)→S(g)+6F(g) ΔH=ΔHf(product)−ΔHf(reactant) ΔH0=ΔH0f(S)+6ΔH0f(F)−ΔH0f(SF6) =275+6×80−(−1100) = 1855 kJmol−1 Also, ΔH0=6ΔHS−F ∴ΔHS−F=18556=309.17=309 kJ mol−1

The average $S - F$ bond energy in $k J m o l^{- 1}$ of $S F_{6}$ is _____.(Rounded off to the nearest integer

[Given : The values of standard enthalpy of formation of $S F_{6} (g), S (g) a n d F (g)$ are - 1100, 275 and 80 kJ $m o l^{- 1}$ respectively]