The average speed at T1K and most probable speed at T2K of CO2 gas is 9 - 104 cm-sec- The values of T1 and T2 are

The correct option is C 1684 K ; 2143 K Average speed = √((8RTπ m)) Most probable speed = √((2RTm)) Average speed at T_1 K = MP speed at ...

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Standard XII

Chemistry

Relating Translational KE and T

The average s...

Question

The average speed at $T_{1} K$ and most probable speed at $T_{2} K$ of $C O_{2}$ gas is $9 \times 10^{4} c m / s e c$ . The values of $T_{1}$ and $T_{2}$ are

2143 K; 1694 K

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1726 K; 2126 K

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1684 K; 2143 K

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1684 K; 3368 K

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Solution

The correct option is C $1684 K; 2143 K$
Average speed = $\sqrt{(\frac{8 R T}{π m})}$

Most probable speed = $\sqrt{(\frac{2 R T}{m})}$

Average speed at $T_{1} K$ = MP speed at $T_{2} K f o r C O_{2}$

$\sqrt{(\frac{8 R T_{1}}{π m})} = \sqrt{(\frac{2 R T_{2}}{m})}$

$\frac{T_{1}}{T_{2}} = \frac{π}{4}$ ------(i)

Also for $C O_{2} u_{m p} = \sqrt{(\frac{2 R T}{m})} = 9 \times 10^{4}$

$= \sqrt{\frac{2 \times 8.314 \times 10^{7} \times T_{2}}{44}} = 9 \times 10^{4}$

By eq (1) We get
$T_{2} = 2143 K$
$T_{1} = 1684 K$
Hence answer is (C)

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The average speed at T1K and most probable speed at T2K of CO2 gas is 9×104cm/sec. The values of T1 and T2 are

The average speed at $T_{1} K$ and most probable speed at $T_{2} K$ of $C O_{2}$ gas is $9 \times 10^{4} c m / s e c$ . The values of $T_{1}$ and $T_{2}$ are