The average speed at T K of CO2 gas is 9-0 - 104 cm s-1- Calculate value of T-

We know, V_avg=√(8RTM) Convert all the given values to standard unitsSo, 9× 10^2 =√(8RTπ× 48) 9× 10^2=0.6641×√(T) T=1836614.7K ...

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Standard XII

Chemistry

Relating Translational KE and T

The average s...

Question

The average speed at $T K$ of $C O_{2}$ gas is $9.0 \times 10^{4} c m s^{- 1}$ . Calculate value of $T$ .

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Solution

We know,
$V_{a v g} = \sqrt{\frac{8 R T}{M}}$
Convert all the given values to standard units
So,
$9 \times 10^{2} = \sqrt{\frac{8 R T}{π \times 48}}$
$⟹ 9 \times 10^{2} = 0.6641 \times \sqrt{T}$
$⟹ T = 1836614.7 K$

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The average speed at T K of CO2 gas is 9.0×104cms−1. Calculate value of T.

We know,Vavg=√8RTMConvert all the given values to standard unitsSo,9×102=√8RTπ×48⟹9×102=0.6641×√T⟹T=1836614.7K

The average speed at $T K$ of $C O_{2}$ gas is $9.0 \times 10^{4} c m s^{- 1}$ . Calculate value of $T$ .

We know,
$V_{a v g} = \sqrt{\frac{8 R T}{M}}$
Convert all the given values to standard units
So,
$9 \times 10^{2} = \sqrt{\frac{8 R T}{π \times 48}}$
$⟹ 9 \times 10^{2} = 0.6641 \times \sqrt{T}$
$⟹ T = 1836614.7 K$